Tutorial 5: Volume Integrals
Question PDF
Class Recording
- Find a volume bounded by the surface , and, .
Solution
- Find the total mass of a spherical object with radius of and with a density function of , where is the radial distance from the center of the sphere.
Solution
- Find the moment of inertia of the following hollow cylinder with constant density along the -axis.
![notion image](https://www.notion.so/image/https%3A%2F%2Ffile.notion.so%2Ff%2Ff%2F6c1b4895-acac-4242-8854-6c16bbcde568%2F28a9ac0e-78a4-4758-960c-9ac117dfa820%2FScreenshot_2022-03-11_at_12.16.55_AM.png%3Fid%3De19dce71-66d6-43d9-8de0-3cd2221d36ad%26table%3Dblock%26spaceId%3D6c1b4895-acac-4242-8854-6c16bbcde568%26expirationTimestamp%3D1722153600000%26signature%3Dkrg-CaLhssaAk42XYcJ3cU3oZyB3XlK5x6ZklpxlS5E?table=block&id=e19dce71-66d6-43d9-8de0-3cd2221d36ad&cache=v2)
Solution
- Find the volume of the following paraboloid. Hint: Inside of the cone boundary is not empty, but it is used to calculate the height upper boundary of the paraboloid ().
![notion image](https://www.notion.so/image/https%3A%2F%2Ffile.notion.so%2Ff%2Ff%2F6c1b4895-acac-4242-8854-6c16bbcde568%2F5fd516d8-35a0-43be-87bd-308f2c99715d%2FScreenshot_2022-03-11_at_12.17.13_AM.png%3Fid%3D25f8fcd0-413f-4bac-bc72-26db492b0f11%26table%3Dblock%26spaceId%3D6c1b4895-acac-4242-8854-6c16bbcde568%26expirationTimestamp%3D1722153600000%26signature%3DSzTZol6ajYywTKuZas3QfoB2DyPGpSvADs6uas3U7UA?table=block&id=25f8fcd0-413f-4bac-bc72-26db492b0f11&cache=v2)
Solution
Radius upper boundary:
Height upper boundary:
Hence, the cylindrical coordinate boundary is: , ,
- Evaluate where is enclosed by , , and .
Solution
We will use cylindrical coordinates to easily solve this sum. Converting the given outer limits of we get:
Since there is no limitation on the values of , we assume it has the values of to . This is also in accordance with the diagram which is obtained by drawing these surfaces.
Also, we substitute in the argument of theΒ integral.
Thus, the integral is,
- Integrate the function over the volume enclose by the planes and , and between the surfaces and .
Solution
Since is expressed as a function of , we should integrate in the direction first. After this we consider theΒ -plane.
The two curves meetΒ at and . We can integrate in or Β first. If we choose , we can seeΒ that the region begins at and ends at , and so is between 0 and 1.
Thus, the integral is,
- Find the volume of the tetrahedron with corners at , , , and .
Solution
The whole problem comes down to correctly describing the region by inequalities:
The lower limit comes from the equation of the line that forms one edge of the tetrahedron in the x-y plane
The upper limit comes from the equation of the plane that forms the βupperβ side of the tetrahedron. Now the volume is
- Find the volume under above the quarter circle inside in the first quadrant.
Solution
- An object occupies the space inside both the cylinder and the sphere , and has density at . Find the total mass.
Solution
- Find the volume bounded by the cylinder and the planes ; .
![notion image](https://www.notion.so/image/https%3A%2F%2Ffile.notion.so%2Ff%2Ff%2F6c1b4895-acac-4242-8854-6c16bbcde568%2F8edccc13-d164-42b4-a9b3-6c37081ea358%2FScreenshot_2022-03-11_at_12.21.48_AM.png%3Fid%3D81b8dab4-163d-4270-a2c0-3feb5c5de89a%26table%3Dblock%26spaceId%3D6c1b4895-acac-4242-8854-6c16bbcde568%26expirationTimestamp%3D1722153600000%26signature%3D9Xoc6NkPso5VJMWZgn_zlbgCQfXn367uBvhL-mu5FoQ?table=block&id=81b8dab4-163d-4270-a2c0-3feb5c5de89a&cache=v2)
Solution
Place the volume element in general position, and integrate to a rod along the -direction. Then integrate the rod over the circle: